I know this is only partly related, but I wonder why the folling
produces no sound, while it does when I set the \freq arg to > 0:
SynthDef(\single_impulse,{
arg gate=1, amp=1, freq=0;
var imp = Impulse.ar(freq);
imp = imp.dup * EnvGen.ar(Env.asr(0,1.0,0.1), gate:gate,
levelScale:amp, doneAction:2);
Out.ar(0, LPF.ar(imp,7400))
}).play(s,[\freq,0])
How come the firts impulse gets swallowed by the filter?
Best,
Karsten
Fredrik Olofsson said :
hi,
(this question is so common it should go into the faq.)
the {}.play construction adds a short envelope and thereby takes
out the
initial impulse. use a synthdef or {Impulse.ar(1)}.play(fadeTime:
0) if
you must.
_f
6 maj 2009 kl. 03.37 skrev Karsten Gebbert:
Hi All,
I found something strange which is at least to me quite
counterintuitive
and feels wrong:
{ Impulse.ar(1) }.play
does not output the first impulse properly (or at all). Is this
intendet behaviour? Can others replicate that? I would expect the
behaviour to be that the first samples output by the ugen is the
impulse
so that:
{ Impulse.ar(0) }.play
would output exactly one impulse and never progress any further.
Am I
wrong in my assumptions or is this a possible bug? I think at least
that
even when supplying a very low value like 0.00001 to the freq
argument
it should definitely output the first impulse no matter what, no?
I use 3.3 on Debian/Lenny.
Thanks to all,
karsten
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