Re: [sc-users] SeqColl windowing?

[James Harkins <jamshark70@xxxxxxxxx>]

I would consider this:

a = (1..9);

((0..6) +.t (0..2)).collect(a[_]);

((0, 2 .. 6) +.t (0..2)).collect(a[_]);

See the Adverbs helpfile. Also I use the property of Array:at that if you pass in an array of indices, you get an array with the values at each corresponding index of the source array, e.g., a[[0, 5]] == [1, 6]

hjh

On Oct 24, 2007, at 7:45 AM, Stefan Kersten wrote:

i'm looking for the nicest way to separate an array into overlapping subarrays, e.g. like this:

[1, 2, 3, 4, 5, 6, 7, 8, 9]

-> [[1, 2, 3], [2, 3, 4], [3, 4, 5], [4, 5, 6], [5, 6, 7], [6, 7, 8], [7, 8, 9]]

-> [[1, 2, 3], [3, 4, 5], [5, 6, 7], [7, 8, 9]]

any suggestions?

thx,

<sk>

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