Re: [sc-users] concatenating and iteration

[Jeremy Zuckerman <jz@xxxxxxxxxxxxxxx>]

ok.  that brings me make to my original approach.  i have a function  
that receives the values for one of its args from a different slider  
each time it's called.
slider1 = EZSlider...
slider2 = EZSlider...
slider3 = EZSlider...
slider4, etc.
//array with the names of all the sliders
slArray = [slider1, slider2, slider3...];

func = {|val|
    val.postln;
};

30.do({ |i|
    func.value(slArray[i])
});

i wasn't sure if there was a good way to avoid the slArray.  that's  
really not a big deal though...  i definitely will need something  
fast so interpret prob won't be good.  thanks for the input everyone.

cheers,
jeremy

On Sep 5, 2005, at 1:45 AM, Till Bovermann wrote:

> Hi,
>
> better do something like
>
> (
> var q = [10, 9, 8, 7];
>
> q.do({|item|
>     item.postln
> })
> )
>
> because of
> 1.) the numbers after q imply, that you want to have an ordered  
> structure
> 2.) String-interpret is always wwaaaaay sloooooow...
> 3.) it looks nicer ;-)
>
> hope that helps
> Till
>
>
> On 05 Sep 2005, at 10:06, Mario Lang wrote:
>
>
> > Jeremy Zuckerman <jz@xxxxxxxxxxxxxxx> writes:
> >
> >
> >
> > > how would i get the values assigned to the vars to return in this
> > > situation:
> > > (
> > > var q0, q1, q2, q3;
> > > q0 = 10; q1=9; q2=8; q3=7;
> > >
> > > 4.do({|i|
> > >     (q++i).postln
> >
> > ("q"++i).interpret.postln
> >
> >
> >
> > >     })
> > > )
> > >
> > > //only i is returned not the values assign to q0, q1, etc.
> > >
> > > thanks!
> >
> > --
> > CYa,
> >   Mario
> >
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>
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