It works but it's inefficient, because it could require as many as
a.size*2 iterations if the max or min item is last in the array (where
Click's version maxes out at a.size iterations).
hjh
On Dec 27, 2007 11:39 AM, Josh Parmenter <josh@xxxxxxxxxxxxxxxxx>
wrote:
would something like this work?
a = [0, 3, 2, 5, 8, 3, 9, 6, 5]
a.indexOf(a.maxItem)
a.indexOf(a.minItem)
--
James Harkins /// dewdrop world
jamshark70@xxxxxxxxxxxxxxxxx
http://www.dewdrop-world.net
"Come said the Muse,
Sing me a song no poet has yet chanted,
Sing me the universal." -- Whitman
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